VB PDU mode 7 bit 解码

新客网 XKER.COM 2004-11-24 来源：收藏本文

Dim tep As String
Dim temp As String
Dim i As Integer
Dim B As Integer
Dim rems As String
tep = rmsg
i = Len(tep)
If i < 1 Then Exit Function

B = i / 2

If i = B * 2 Then
tep = Left(tep, B * 2)
Else
B = B - 1
tep = Left(tep, B * 2)
End If

chg7 = ""
rems = ""
Dim trint As Integer
Dim strtmp As String

trint = 1
strtmp = ""

For i = 1 To B
temp = "&H" & Mid(tep, (i - 1) * 2 + 1, 2)
temp = D_To_B(Val(temp)) '转二进制

If Len(temp) < 8 Then
temp = strpla(8 - Len(temp)) + temp
End If

strtmp = Mid(temp, trint + 1, 8 - trint) + rems

rems = Mid(temp, 1, trint)

chg7 = chg7 & ChrW(CInt(Val(B_To_D(strtmp))))

trint = trint + 1
If trint = 8 Then
trint = 1
chg7 = chg7 & ChrW(CInt(Val(B_To_D(rems))))
rems = ""
End If

Next i

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