存储过程、存储函数的加密：WITH ENCRYPTION
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CREATE procedure dbo.sp_XML_main

@table_name nvarchar(260)=’’,

@dirname nvarchar(20)=’’

WITH ENCRYPTION

as

begin

....................

end

go

存储过程、存储函数的解密

if exists (select * from dbo.sysobjects where id = object_id(N’[dbo].[sp_decrypt]’) and OBJECTPROPERTY(id, N’IsProcedure’) = 1)

drop procedure [dbo].[sp_decrypt]

GO

/*--破解函数,过程,触发器,视图.仅限于SQLSERVER2000

--作者:J9988-- All rights reserved*/

/*--调用示例

--解密指定存储过程

exec sp_decrypt ’AppSP_test’

--对所有的存储过程解密

declare tb cursor for

select name from sysobjects where xtype=’P’ and status>0 and name<>’sp_decrypt’

declare @name sysname

open tb

fetch next from tb into @name

while @@fetch_status=0

begin

print ’/*-------存储过程 [’+@name+’] -----------*/’

exec sp_decrypt @name

fetch next from tb into @name

end

close tb

deallocate tb

--*/

if exists (select * from dbo.sysobjects where id = object_id(N’[dbo].[SP_DECRYPT]’) and OBJECTPROPERTY(id, N’IsProcedure’) = 1)

drop procedure [dbo].[SP_DECRYPT]

GO

CREATE PROCEDURE sp_decrypt(@objectName varchar(50))

AS

begin

set nocount on

--破解字节不受限制，适用于SQLSERVER2000存储过程，函数，视图，触发器

--修正上一版视图触发器不能正确解密错误

--发现有错，请E_MAIL：CSDNj9988@tom.com
begin tran

declare @objectname1 varchar(100),@orgvarbin varbinary(8000)

declare @sql1 nvarchar(4000),@sql2 varchar(8000),@sql3 nvarchar(4000),@sql4 nvarchar(4000)

DECLARE @OrigSpText1 nvarchar(4000), @OrigSpText2 nvarchar(4000) , @OrigSpText3 nvarchar(4000), @resultsp nvarchar(4000)

declare @i int,@status int,@type varchar(10),@parentid int

declare @colid int,@n int,@q int,@j int,@k int,@encrypted int,@number int

select @type=xtype,@parentid=parent_obj from sysobjects where id=object_id(@ObjectName)

create table #temp(number int,colid int,ctext varbinary(8000),encrypted int,status int)

insert #temp SELECT number,colid,ctext,encrypted,status FROM syscomments WHERE id = object_id(@objectName)

select @number=max(number) from #temp

set @k=0

while @k<=@number

begin

if exists(select 1 from syscomments where id=object_id(@objectname) and number=@k)

begin

if @type=’P’

set @sql1=(case when @number>1 then ’ALTER PROCEDURE ’+ @objectName +’;’+rtrim(@k)+’ WITH ENCRYPTION AS ’

else ’ALTER PROCEDURE ’+ @objectName+’ WITH ENCRYPTION AS ’

end)

if @type=’TR’

begin